Important Equations.

Example Problems Problem 1 a When a potential difference of 12 V is applied to a wire of radius 0. What is the resistivity of the wire? Solutions b The resistance of a bagel toaster is To prepare a bagel, the toaster is operated for one minute from a V outlet. What is the current through the toaster? How much energy is delivered to the toaster? Solutions Problem 2 A circuit containing six resistors is connected to a V power supply as shown in the figure below.

Solutions Applets and Animations. A simple DC circuit has a DC voltage source lighting a light bulb. Also shown is a hydraulic system in which water drives a turbine.

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The two systems are shown to be similar. Look inside a battery to see how it works. Select the battery voltage and little stick figures move charges from one end of the battery to the other. A voltmeter tells you the resulting battery voltage. We can treat the parallel networks like the equivalent resistors so the circuit we are currently dealing with looks like:. To determine the power we need the resistance which we have calculated and either the voltage or current. The two resistors are in parallel so the voltage across them is the same as well as the same as the voltage across the parallel network.

You can do it! Let us help you to study smarter to achieve your goals. Siyavula Practice guides you at your own pace when you do questions online. We first need to find the current. Recall from grade 10 that current is charge divided by total time in seconds :. Now we have a circuit with two resistors in series so we can calculate the equivalent resistance:.

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Next we find the voltage across this resistor and use this to find the voltage across the parallel combination:. This is the voltage across each of the parallel resistors.

### A closed loop through which current can flow.

So we can find the power dissipated by each of these resistors:. Now we have a circuit with three resistors in series so we can calculate the equivalent resistance:. This is the current in the two series resistor and through the entire parallel connection.

Using this we can find the power dissipated in the two series resistors:. Next we find the voltage across each of these resistors and use this to find the voltage across the parallel combination:.

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We start by calculating the equivalent resistance of the resistors. We know the total power and the total voltage, so we use that to find the total resistance.

## NPTEL :: Electrical Engineering - NOC:Basic Electric Circuits

This is the current in the series resistor and through the entire parallel connection. Using this we can find the power dissipated in the series resistor:. Next we find the voltage across this resistors and use this to find the voltage across the parallel combination:.

For a series circuit the total current is equal to the current in each of the resistors. We know the resistance, the voltage and the current for this resistor so we can use any two of these to find the power. We will use the resistance and the current:. We are given the total current and this is the current in the series resistor and through the entire parallel connection. When power is dissipated in a device there is a transfer of energy from one kind to another. The basis of our physical world is electrical. The unified Electromagnetic field can appear to us as particles, i.

A close interrelation therefore exists between matter and electric energy. This knowledge is extensively utilized in technology. Various tools and instruments are electrically powered, utilizing the exceedingly important principle of closed electric circuits.